Optimal. Leaf size=163 \[ -\frac{2 c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{a^{3/2}}+\frac{d^{3/2} (5 b c-3 a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{b^{5/2}}-\frac{d \sqrt{a+b x} \sqrt{c+d x} (2 b c-3 a d)}{a b^2}+\frac{2 (c+d x)^{3/2} (b c-a d)}{a b \sqrt{a+b x}} \]
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Rubi [A] time = 0.145219, antiderivative size = 163, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {98, 154, 157, 63, 217, 206, 93, 208} \[ -\frac{2 c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{a^{3/2}}+\frac{d^{3/2} (5 b c-3 a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{b^{5/2}}-\frac{d \sqrt{a+b x} \sqrt{c+d x} (2 b c-3 a d)}{a b^2}+\frac{2 (c+d x)^{3/2} (b c-a d)}{a b \sqrt{a+b x}} \]
Antiderivative was successfully verified.
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Rule 98
Rule 154
Rule 157
Rule 63
Rule 217
Rule 206
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{(c+d x)^{5/2}}{x (a+b x)^{3/2}} \, dx &=\frac{2 (b c-a d) (c+d x)^{3/2}}{a b \sqrt{a+b x}}+\frac{2 \int \frac{\sqrt{c+d x} \left (\frac{b c^2}{2}-\frac{1}{2} d (2 b c-3 a d) x\right )}{x \sqrt{a+b x}} \, dx}{a b}\\ &=-\frac{d (2 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{a b^2}+\frac{2 (b c-a d) (c+d x)^{3/2}}{a b \sqrt{a+b x}}+\frac{2 \int \frac{\frac{b^2 c^3}{2}+\frac{1}{4} a d^2 (5 b c-3 a d) x}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx}{a b^2}\\ &=-\frac{d (2 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{a b^2}+\frac{2 (b c-a d) (c+d x)^{3/2}}{a b \sqrt{a+b x}}+\frac{c^3 \int \frac{1}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx}{a}+\frac{\left (d^2 (5 b c-3 a d)\right ) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{2 b^2}\\ &=-\frac{d (2 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{a b^2}+\frac{2 (b c-a d) (c+d x)^{3/2}}{a b \sqrt{a+b x}}+\frac{\left (2 c^3\right ) \operatorname{Subst}\left (\int \frac{1}{-a+c x^2} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{a}+\frac{\left (d^2 (5 b c-3 a d)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{b^3}\\ &=-\frac{d (2 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{a b^2}+\frac{2 (b c-a d) (c+d x)^{3/2}}{a b \sqrt{a+b x}}-\frac{2 c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{a^{3/2}}+\frac{\left (d^2 (5 b c-3 a d)\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{b^3}\\ &=-\frac{d (2 b c-3 a d) \sqrt{a+b x} \sqrt{c+d x}}{a b^2}+\frac{2 (b c-a d) (c+d x)^{3/2}}{a b \sqrt{a+b x}}-\frac{2 c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{a^{3/2}}+\frac{d^{3/2} (5 b c-3 a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{b^{5/2}}\\ \end{align*}
Mathematica [C] time = 1.40469, size = 274, normalized size = 1.68 \[ -\frac{2 \left (b c \left (\sqrt{b c-a d} \sqrt{\frac{b (c+d x)}{b c-a d}} \left (b c^{3/2} \sqrt{a+b x} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )+\sqrt{a} \sqrt{c+d x} (a d-b c)\right )-a^{3/2} d^{3/2} \sqrt{a+b x} \sqrt{c+d x} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b c-a d}}\right )\right )+a^{3/2} d \sqrt{c+d x} (b c-a d)^{3/2} \, _2F_1\left (-\frac{3}{2},-\frac{1}{2};\frac{1}{2};\frac{d (a+b x)}{a d-b c}\right )\right )}{a^{3/2} b^2 \sqrt{a+b x} \sqrt{b c-a d} \sqrt{\frac{b (c+d x)}{b c-a d}}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.02, size = 492, normalized size = 3. \begin{align*} -{\frac{1}{2\,{b}^{2}a}\sqrt{dx+c} \left ( 3\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) x{a}^{2}b{d}^{3}\sqrt{ac}-5\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) xa{b}^{2}c{d}^{2}\sqrt{ac}+2\,\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }+2\,ac}{x}} \right ) x{b}^{3}{c}^{3}\sqrt{bd}+3\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}{a}^{3}{d}^{3}-5\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}{a}^{2}bc{d}^{2}+2\,\sqrt{bd}\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }+2\,ac}{x}} \right ) a{b}^{2}{c}^{3}-2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}\sqrt{ac}xab{d}^{2}-6\,\sqrt{bd}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{ac}{a}^{2}{d}^{2}+8\,\sqrt{bd}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{ac}abcd-4\,\sqrt{bd}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{ac}{b}^{2}{c}^{2} \right ){\frac{1}{\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }}}{\frac{1}{\sqrt{bd}}}{\frac{1}{\sqrt{ac}}}{\frac{1}{\sqrt{bx+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 17.1506, size = 2603, normalized size = 15.97 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c + d x\right )^{\frac{5}{2}}}{x \left (a + b x\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.79135, size = 440, normalized size = 2.7 \begin{align*} -\frac{2 \, \sqrt{b d} c^{3}{\left | b \right |} \arctan \left (-\frac{b^{2} c + a b d -{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}}{2 \, \sqrt{-a b c d} b}\right )}{\sqrt{-a b c d} a b} + \frac{\sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d} \sqrt{b x + a} d^{2}{\left | b \right |}}{b^{4}} - \frac{{\left (5 \, \sqrt{b d} b c d{\left | b \right |} - 3 \, \sqrt{b d} a d^{2}{\left | b \right |}\right )} \log \left ({\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )}{2 \, b^{4}} + \frac{4 \,{\left (\sqrt{b d} b^{3} c^{3}{\left | b \right |} - 3 \, \sqrt{b d} a b^{2} c^{2} d{\left | b \right |} + 3 \, \sqrt{b d} a^{2} b c d^{2}{\left | b \right |} - \sqrt{b d} a^{3} d^{3}{\left | b \right |}\right )}}{{\left (b^{2} c - a b d -{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )} a b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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